Assigment 5

1.Prove if C bisector of PAQ angle and AP =AQ . So, APC angle congruent with AQC angle!
Answer:
Triangle APQ, AP ≈ (congruent) AQ
AP = line segment af AP
Angle APC ≈ angle AQC
• AP ≈ AQ (measure of AP = AQ)
• Э C € PQ ( exsistence one point in line segment )
• Э AC ( exsistence line segment from two point)
• Э < QAC and < PAC ( existence of angles)
• Э ! AC
< QAC ≈ < PAC ( existence bisector of angle)
• ∆ QAC and ∆ PAC (existence teiangle)

AP ≈ AQ (given)
AC = AC ( reflektif)
< QAC ≈ < PAC
• ∆ QAC ≈ ∆ PAC (existence side – angle - side)
• Because ∆ QAC ≈ ∆ PAC,
So, PC ≈ QC
< PCA ≈ < QCA
< APC ≈ < AQC
So, we can prove that APC angle congruent with AQC angle